Integrand size = 21, antiderivative size = 67 \[ \int \cos (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \, dx=\frac {\operatorname {Hypergeometric2F1}\left (\frac {1}{4},-p,\frac {5}{4},-\frac {b \sin ^4(e+f x)}{a}\right ) \sin (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \left (1+\frac {b \sin ^4(e+f x)}{a}\right )^{-p}}{f} \]
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Time = 0.05 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {3302, 252, 251} \[ \int \cos (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \, dx=\frac {\sin (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \left (\frac {b \sin ^4(e+f x)}{a}+1\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {1}{4},-p,\frac {5}{4},-\frac {b \sin ^4(e+f x)}{a}\right )}{f} \]
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Rule 251
Rule 252
Rule 3302
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \left (a+b x^4\right )^p \, dx,x,\sin (e+f x)\right )}{f} \\ & = \frac {\left (\left (a+b \sin ^4(e+f x)\right )^p \left (1+\frac {b \sin ^4(e+f x)}{a}\right )^{-p}\right ) \text {Subst}\left (\int \left (1+\frac {b x^4}{a}\right )^p \, dx,x,\sin (e+f x)\right )}{f} \\ & = \frac {\operatorname {Hypergeometric2F1}\left (\frac {1}{4},-p,\frac {5}{4},-\frac {b \sin ^4(e+f x)}{a}\right ) \sin (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \left (1+\frac {b \sin ^4(e+f x)}{a}\right )^{-p}}{f} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 67, normalized size of antiderivative = 1.00 \[ \int \cos (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \, dx=\frac {\operatorname {Hypergeometric2F1}\left (\frac {1}{4},-p,\frac {5}{4},-\frac {b \sin ^4(e+f x)}{a}\right ) \sin (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \left (1+\frac {b \sin ^4(e+f x)}{a}\right )^{-p}}{f} \]
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\[\int \cos \left (f x +e \right ) {\left (a +b \left (\sin ^{4}\left (f x +e \right )\right )\right )}^{p}d x\]
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\[ \int \cos (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \, dx=\int { {\left (b \sin \left (f x + e\right )^{4} + a\right )}^{p} \cos \left (f x + e\right ) \,d x } \]
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Timed out. \[ \int \cos (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \, dx=\text {Timed out} \]
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\[ \int \cos (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \, dx=\int { {\left (b \sin \left (f x + e\right )^{4} + a\right )}^{p} \cos \left (f x + e\right ) \,d x } \]
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\[ \int \cos (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \, dx=\int { {\left (b \sin \left (f x + e\right )^{4} + a\right )}^{p} \cos \left (f x + e\right ) \,d x } \]
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Time = 13.77 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.96 \[ \int \cos (e+f x) \left (a+b \sin ^4(e+f x)\right )^p \, dx=\frac {\sin \left (e+f\,x\right )\,{\left (b\,{\sin \left (e+f\,x\right )}^4+a\right )}^p\,{{}}_2{\mathrm {F}}_1\left (\frac {1}{4},-p;\ \frac {5}{4};\ -\frac {b\,{\sin \left (e+f\,x\right )}^4}{a}\right )}{f\,{\left (\frac {b\,{\sin \left (e+f\,x\right )}^4}{a}+1\right )}^p} \]
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